public class Solution { //Time: O(n^2) Space: O(1) public int threeSumClosest(int[] num, int target) { if (num == null || num.length < 3) { return -1; } Arrays.sort(num); int closest = Integer.MAX_VALUE / 2; for (int i = 0; i < num.length; i++) { int left = i + 1; int right = num.length - 1; while (left < right) { int cur = num[i] + num[left] + num[right]; if (Math.abs(cur - target) < Math.abs(closest - target)) { closest = cur; if (closest == target) { return target; } } if (cur < target) { left++; } else if (cur > target) { right--; } } } return closest; } }
Tuesday, July 22, 2014
2Sum && 3Sum && 3Sum Closest && 4Sum
3Sum Closest
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