public class Solution {
//Time: O(n^2) Space: O(1)
public int threeSumClosest(int[] num, int target) {
if (num == null || num.length < 3) {
return -1;
}
Arrays.sort(num);
int closest = Integer.MAX_VALUE / 2;
for (int i = 0; i < num.length; i++) {
int left = i + 1;
int right = num.length - 1;
while (left < right) {
int cur = num[i] + num[left] + num[right];
if (Math.abs(cur - target) < Math.abs(closest - target)) {
closest = cur;
if (closest == target) {
return target;
}
}
if (cur < target) {
left++;
} else if (cur > target) {
right--;
}
}
}
return closest;
}
}
Tuesday, July 22, 2014
2Sum && 3Sum && 3Sum Closest && 4Sum
3Sum Closest
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