Given a set of distinct integers, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If S = [1,2,3], a solution is:
If S = [1,2,3], a solution is:
[
[3],
[1],
[2],
[1,2,3],
[1,3],
[2,3],
[1,2],
[]
]
就是一个DFS的过程,需要一个额外的index变量。注意这道题我们需要先sort下数组,这样才能保证升序。
public class Solution { //Time: O(n^n) public ArrayList<ArrayList<Integer>> subsets(int[] S) { ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>(); ArrayList<Integer> tmp = new ArrayList<Integer>(); Arrays.sort(S); subsetHelp(res, tmp, S, 0); return res; } private void subsetHelp(ArrayList<ArrayList<Integer>> res, ArrayList<Integer> tmp, int[] S, int index) { res.add(new ArrayList<Integer>(tmp)); for (int i = index; i < S.length; i++) { tmp.add(S[i]); subsetHelp(res, tmp, S, i + 1); tmp.remove(tmp.size() - 1); } } }
Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets.
一样DFS,但是对于相邻两个元素相同的情况下,必须避免重复case。
public class Solution { //Time: O(n^n) public ArrayList<ArrayList<Integer>> subsetsWithDup(int[] num) { ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>(); ArrayList<Integer> tmp = new ArrayList<Integer>(); Arrays.sort(num); subsetsHelp(res, tmp, num, 0); return res; } private void subsetsHelp(ArrayList<ArrayList<Integer>> res, ArrayList<Integer> tmp, int[] num, int index) { res.add(new ArrayList<Integer>(tmp)); for (int i = index; i < num.length; i++) { if (i != index && num[i] == num[i - 1]) { continue; } tmp.add(num[i]); subsetsHelp(res, tmp, num, i + 1); tmp.remove(tmp.size() - 1); } } }
No comments:
Post a Comment