Given a set of distinct integers, S, return all possible subsets.
Note:
- Elements in a subset must be in non-descending order.
- The solution set must not contain duplicate subsets.
For example,
If S = [1,2,3], a solution is:
If S = [1,2,3], a solution is:
[
[3],
[1],
[2],
[1,2,3],
[1,3],
[2,3],
[1,2],
[]
]
就是一个DFS的过程,需要一个额外的index变量。注意这道题我们需要先sort下数组,这样才能保证升序。
public class Solution {
//Time: O(n^n)
public ArrayList<ArrayList<Integer>> subsets(int[] S) {
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
ArrayList<Integer> tmp = new ArrayList<Integer>();
Arrays.sort(S);
subsetHelp(res, tmp, S, 0);
return res;
}
private void subsetHelp(ArrayList<ArrayList<Integer>> res, ArrayList<Integer> tmp,
int[] S, int index) {
res.add(new ArrayList<Integer>(tmp));
for (int i = index; i < S.length; i++) {
tmp.add(S[i]);
subsetHelp(res, tmp, S, i + 1);
tmp.remove(tmp.size() - 1);
}
}
}
Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets.
一样DFS,但是对于相邻两个元素相同的情况下,必须避免重复case。
public class Solution {
//Time: O(n^n)
public ArrayList<ArrayList<Integer>> subsetsWithDup(int[] num) {
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
ArrayList<Integer> tmp = new ArrayList<Integer>();
Arrays.sort(num);
subsetsHelp(res, tmp, num, 0);
return res;
}
private void subsetsHelp(ArrayList<ArrayList<Integer>> res, ArrayList<Integer> tmp,
int[] num, int index) {
res.add(new ArrayList<Integer>(tmp));
for (int i = index; i < num.length; i++) {
if (i != index && num[i] == num[i - 1]) {
continue;
}
tmp.add(num[i]);
subsetsHelp(res, tmp, num, i + 1);
tmp.remove(tmp.size() - 1);
}
}
}
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