Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
设置一个最大和最小值,同时更新。
public class Solution {
//Time: O(n)
public boolean isValidBST(TreeNode root) {
return isValid(root, Integer.MAX_VALUE, Integer.MIN_VALUE);
}
private boolean isValid(TreeNode root, int max, int min) {
if (root == null) {
return true;
}
if (root.val >= max || root.val <= min) {
return false;
}
return isValid(root.left, root.val, min) && isValid(root.right, max, root.val);
}
}
用类似一个inorder的方法,灵感来自recover BST。
public class Solution {
private TreeNode last = null;
public boolean isValidBST(TreeNode root) {
if (root == null) {
return true;
}
boolean left = isValidBST(root.left);
if (last != null && last.val >= root.val) {
return false;
}
last = root;
boolean right = isValidBST(root.right);
return left && right;
}
}
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