Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
当发现相邻node值一样,记录这个值,把下面和这个值相等的Node都删除。注意Null check。
public class Solution {
//Time: O(n) Space: O(1)
public ListNode deleteDuplicates(ListNode head) {
if (head == null || head.next == null) {
return head;
}
ListNode dummy = new ListNode(0);
dummy.next = head;
head = dummy;
while (head.next != null) {
if (head.next.next != null && head.next.val == head.next.next.val) {
int val = head.next.val;
while (head.next != null && head.next.val == val) {
head.next = head.next.next;
}
} else {
head = head.next;
}
}
return dummy.next;
}
}
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