Given a string S and a string T, count the number of distinct subsequences of T in S.
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ACE" is a subsequence of "ABCDE" while "AEC" is not).
Here is an example:
S = "rabbbit", T = "rabbit"
S = "rabbbit", T = "rabbit"
Return 3.
用一个二维数组进行DP,map[i][j] 表示T在长度前j位在S长度前i位合法的个数。当第i位和第j位char不同,我们只能考虑删掉第i位,相同时还能考虑保留第i为。
public class Solution { //Time: O(m * n) Space: O(m * n) public int numDistinct(String S, String T) { if (S.length() < T.length()) { return 0; } int m = S.length(); int n = T.length(); int[][] map = new int[m + 1][n + 1]; for (int i = 0; i <= m; i++) { map[i][0] = 1; } for (int i = 1; i <= m; i++) { for (int j = 1; j <= n; j++) { map[i][j] += map[i - 1][j]; if (S.charAt(i - 1) == T.charAt(j - 1)) { map[i][j] += map[i - 1][j - 1]; } } } return map[m][n]; } }
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