You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Output: 7 -> 0 -> 8
只要最后检查下进位是不是1。
public class Solution {
//Time: O(n)
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
int carry = 0;
ListNode dummy = new ListNode(0);
ListNode node = dummy;
while (l1 != null || l2 != null) {
if (l1 != null) {
carry += l1.val;
l1 = l1.next;
}
if (l2 != null) {
carry += l2.val;
l2 = l2.next;
}
node.next = new ListNode(carry % 10);
carry /= 10;
node = node.next;
}
if (carry == 1) {
node.next = new ListNode(1);
}
return dummy.next;
}
}
No comments:
Post a Comment