You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Output: 7 -> 0 -> 8
只要最后检查下进位是不是1。
public class Solution { //Time: O(n) public ListNode addTwoNumbers(ListNode l1, ListNode l2) { if (l1 == null) { return l2; } if (l2 == null) { return l1; } int carry = 0; ListNode dummy = new ListNode(0); ListNode node = dummy; while (l1 != null || l2 != null) { if (l1 != null) { carry += l1.val; l1 = l1.next; } if (l2 != null) { carry += l2.val; l2 = l2.next; } node.next = new ListNode(carry % 10); carry /= 10; node = node.next; } if (carry == 1) { node.next = new ListNode(1); } return dummy.next; } }
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