There are N gas stations along a circular route, where the amount of gas at station i is gas[i].
You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
The solution is guaranteed to be unique.
比较直观的是从每个地点开始,但是这题可以只遍历一遍,假设从1开始到4,发现不能走了,说明2,3,4开始也不行。最后检查下,总油量是否大于总消耗。
public class Solution { //Time: O(n) Space: O(1); public int canCompleteCircuit(int[] gas, int[] cost) { int sum = 0; int cur = 0; int index = 0; for (int i = 0; i < gas.length; i++) { cur += gas[i] - cost[i]; sum += gas[i] - cost[i]; if (cur < 0) { cur = 0; index = i + 1; } } return sum < 0 ? -1 : index; } }
No comments:
Post a Comment