Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.
用一个stack,如果是括号左边push,右边就和pop出来的比较是否为一对(检查stack是否已经为空)。最后检查遍历完后,stack是否为空。
public class Solution { //Time: O(n) public boolean isValid(String s) { if (s == null || s.length() == 0) { return false; } HashMap<Character, Character> map = new HashMap<Character, Character>(); map.put('(', ')'); map.put('[', ']'); map.put('{', '}'); Stack<Character> stack = new Stack<Character>(); for (int i = 0; i < s.length(); i++) { if (map.containsKey(s.charAt(i))) { stack.push(s.charAt(i)); } else { if (stack.isEmpty() || map.get(stack.peek()) != s.charAt(i)) { return false; } stack.pop(); } } if (!stack.isEmpty()) { return false; } return true; } }
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